2023 NECO Chemistry Practical Question And Answers Now Available
Are you looking for the real 2023 NECO Chemistry Practical Specimen answers? Are you looking for the instructions on how to carry out the 2023 chemistry Practical for NECO? Here is the good news: the NECO 2023 chemistry Practical Specimen has been released. All science students who are taking this examination are expected to study them before hand. If so, this post is for you.
Is the real NECO Chemistry Practical Specimen Out for 2023?
Yes, the legit and latest specimen (syllabus) for this year’s NECO chemistry examination has just been released. All you need is to sit back, study it and get ready to pass your exams.
Real NECO Chemistry Practical Questions Below.
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NECO CHEMISTRY PRACTICAL SOLUTIONS
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(1a)
[TABULATE]
Burette Reading (cm³) | Rough | Titration I | Titration II
Final Reading (cm³) | 21.50 | 43.00 | 22.00
Initial Reading (cm³) | 0.00 | 21.50 | 00.00
Volume of A used (cm³) | 21.50 | 21.50 | 22.00
(1ai)
Average Volume of acid used = 21.50 + 21.50/2 = 21.50cm³
(1aii)
Solution B[Sodium trioxocarbonate (iv)] feels soapy
(1bi)
Conc. B in mol/dm³ =?
Ca= 0.04, Va= 21.50cm³, na= 1
Cb= ? , Vb= 25.00cm³ nb= 1
CaVa/CbVb = na/nb = 0.04×21.50/Cb×25.00 = 1/1
Cb= 0.04×21.50/25.00 = 0.86/25.00
Cb= 0.0344mol/dm³
(1bii)
Conc. of B in g/dm³ = Conc. of B in mol/dm³ × molar mass of B
Molar mass of B(NaCO₃)= (23×2) + 12 + (16×3) = 106
:. Conc. of B in g/dm³ = 0.0344×106 = 3.6g/dm³
(1biii)
1 mole of Na₂Co₃ = 1mole of Na₂So₄
:. 0.0344 mole of Na₂Co₃ = 0.0344 mole of Na₂So₄
№ of mole= mass/ molar mass
Molar mass of Na₂So₄= (23×2)+32+(16×4)=142
:. 0.0344 = mass/142
Mass=142×0.0344=4.9g
(1biv)
1 mole of Na₂Co₃= 1 mole of CO₂
0.0344 mole of Na₂Co₃ = 0.0344 mole of CO₂
:. № of mole = volume/ molar volume = 0.0344 = volume of CO₂/22400cm³
=771cm³
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(2ai)
[TABULATE]
=TEST=
C + heat
=OBSERVATION=
Formation of yellow flame
=INFERENCE=
Na⁺ present
(2aii)
=TEST=
C + distilled water + shake
=OBSERVATION=
It readily dissolve in water
=INFERENCE=
C is a soluble in water
(2aiii)
=TEST=
Solution C + litmus paper
=OBSERVATION=
It changes moist red litmus to blue and no effect blue
=INFERENCE=
Solution C is alkaline
(2bi)
=TEST=
1st portion of solution C + barium chloride
=OBSERVATION=
White precipitate formed
=INFERENCE=
CO₃²⁻ , SO₄²⁻ , S²⁻ or SO₃²⁻
(2bii)
=TEST=
Add dilute HCl to product in (bi)
=OBSERVATION=
White precipitate dissolved
=INFERENCE=
CO₃ , SO₃²⁻ or S₃²⁻
(2biii)
=TEST=
To the second portion add phenolphthalein
=OBSERVATION=
Purple colour observed
=INFERENCE=
C is alkaline
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(3ai)
Sulphur (iv) oxide and hydrogen sulphide.
(3aii)
Liberation of hydrogen gas with pop sound and formation of green iron (ii) chloride solution
(3aiii)
Spatula, beaker, weighing balance, standard volumetric flask
(3bi)
Solution turns red
(3bii)
Turns from brown to green
(3biii)
A colourless, odourless, acidic gas liberated which turns blue litmus paper red and turn lime water milky.
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